Answer with Explanation:
The force of attraction between 2 charges of magnitude[tex]q_1,q_2[/tex] separated by a distance 'r' is given by
[tex]F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}[/tex]
where
[tex]\epsilon _o[/tex] is a constant known as permitivity of free space
[tex]k=9\times 10^{9}Nm^2/C^2[/tex]
Applying the given values in the above relation we get
[tex]8=9\times 10^{9}\times \frac{130\times 180}{r^{2}}\\\\r^{2}=\frac{9\times 10^{9}\times 130\times 180}{8}\\\\r^{2}=26325\times 10^{9}\\\\\therefore r=\sqrt{26325\times 10^{9}}=5.131\times 10^{6}meters[/tex]
