Answer:
a) 0.12 m
b) 0.24 m
Explanation:
[tex]f_0[/tex]= Fundamental frequency = 707 Hz
Speed of sound = 343 m/s
Length of the piece of conduit
a) Closed at one end
[tex]f_0=\frac{v}{4L}\\\Rightarrow L=\frac{v}{4f_0}\\\Rightarrow L=\frac{343}{4\times 707}\\\Rightarrow L=0.12\ m[/tex]
Length of conduit = 0.12 m
a) Open at both ends
[tex]f_0=\frac{v}{2L}\\\Rightarrow L=\frac{v}{2f_0}\\\Rightarrow L=\frac{343}{2\times 707}\\\Rightarrow L=0.24\ m[/tex]
Length of conduit = 0.24 m