Respuesta :
Since the exponent (-3) is negative, flip the expression to: 1/(5n^4)^3.
Notice how the negative exponent becomes positive as you flip it.
Now evaluate the powers in the denominator: 1/((5^3)(n^4)^3
I separated the constant (5) from the variable (n) to show you how the powers are evaluated.
1/(5x5x5)(nxnxnxn)(nxnxnxn)(nxnxnxn)
—-> the power four means that there are 4 multiples of n in the parentheses. The power 3 corresponds to how many groups.
1/(125)(n^12)
= 1/125n^12
Notice how the negative exponent becomes positive as you flip it.
Now evaluate the powers in the denominator: 1/((5^3)(n^4)^3
I separated the constant (5) from the variable (n) to show you how the powers are evaluated.
1/(5x5x5)(nxnxnxn)(nxnxnxn)(nxnxnxn)
—-> the power four means that there are 4 multiples of n in the parentheses. The power 3 corresponds to how many groups.
1/(125)(n^12)
= 1/125n^12
Inverse law of indices are written as negative indices. The resulting expression after simplification is [tex]\frac{1}{125n^{12}}[/tex]
Law of indices
According to the law of indices
[tex]a^{-n}=1/n[/tex]
Given the indices expression
[tex](5n^4)^{-3}[/tex]
This can be written as a fraction to have:
[tex](5n^4)^{-3} = \frac{1}{(5n^4)^3} \\(5n^4)^{-3} = \frac{1}{125n^{12}}[/tex]
Hence the resulting expression after simplification is [tex]\frac{1}{125n^{12}}[/tex]
Learn more on indices here: https://brainly.com/question/10339517
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