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A circular loop of wire of radius 0.50 m is in a uniform magnetic field of 0.30 T. The current in the loop is 2.0 A. What is the magnetic torque when the plane of the loop is parallel to the magnetic field? B) 0.41 mN D)0.47 mN E)0.52 mN A) 0.59 m-N C) zero

Respuesta :

Answer:

D)Ï„=0.47 N.m

Explanation:

Given that

Radius,r=0.5 m

magnetic field ,B=0.3 T

Current ,I=2 A

As we know that torque on the the loop due magnetic field given as

τ=I A B sinθ

Where θ is the angle between magnetic flied and area vector of loop.

Plane of loop is parallel to magnetic field it means that

θ=90°

So

τ=2 x π x 0.5 x 0.5  x 0.3 x sin90° N.m

Ï„=0.47 N.m

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