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a rear wheel drive car of mass 1000kg is accelerating with a constant acceleration without slipping from 0 to 60m/s in one minute. what will be the friction force on each rear wheel of the car?

Respuesta :

Answer:

Fs = 500 Newton

Explanation:

Given data:

Mass = 1000 kg

Initial speed = 0 m/s

Final speed = 60 m/s

By equation of motion we know that

v = u + at

[tex]60 = 0 + a\times 60\ sec[/tex]

Therefore a is = 1 m/s^2

From Newton's second law

[tex]Fs + Fs = ma[/tex]

where Fs is friction on each rear wheel

[tex]2Fs = 1000\times1[/tex]

2Fs = 1000

Fs = 500 Newton

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