Answer:
The frequency is 65.25 Hz.
Explanation:
Given that,
Capacitor = 9.38 μF
Reactant = 260.0 ohm
We need to calculate the frequency
Using formula of reactant
[tex]X_{c}=\dfrac{1}{2\pi fC}[/tex]
Where, f = frequency
C = capacitor
[tex]X_{c}[/tex] =reactant
Put the value in to the formula
[tex]260.0=\dfrac{1}{2\times\pi\times f\times9.38\times10^{6}}[/tex]
[tex]f=\dfrac{1}{2\times\pi\times9.38\times10^{-6}\times260.0}[/tex]
[tex]f=65.25\ Hz[/tex]
Hence, The frequency is 65.25 Hz
