Answer:
691 m
Explanation:
In these problems the time a ball is in the air is determined by the gravitational acceleration (y-coordinate) and the distance it travels is related to the velocity in the x-coordinate.
First get the x and y components of the initial speed.
Initial speed has a magnitude of 125 and a direction of 30°
speed in x = 125 cos 30° = 108.3 m/s
speed in y = 125 sin 30° = 62.5 m/s
The time it takes to the ball to reach the highest height (when the speed in the y-coordinate is 0) is:
[tex]v_{f} =v_{i}+at[/tex]
[tex]v_{f}:Final \ speed \\v_{i}: Initial \ speed \\a: Acceleration\ (gravitational\ acceleration) \\t: Time[/tex]
0 = 62.5 - 9.8*t
t = 6.38 s
With the time you can calculate the distance travelled in the x-coordinate at a constant speed of 108.3.
d = vt
d = 108.3 * 6.38
d = 691 m
