12x+7<-11 or 5x-8>40

Answer:
A
Step-by-step explanation:
Given
12x + 7 < - 11 or 5x - 8 > 40
Solve each inequality
12x + 7 < - 11 ( subtract 7 from both sides )
12x < - 18 ( divide both sides by 12 )
x < - [tex]\frac{3}{2}[/tex]
OR
5x - 8 > 40 ( add 8 to both sides )
5x > 48 ( divide both sides by 5 )
x > [tex]\frac{48}{5}[/tex]
Solution is
x < - [tex]\frac{3}{2}[/tex] or x > [tex]\frac{48}{5}[/tex] → A