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chloepenney

Answer:

1.62 × 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

Explanation:

To find the amount of atoms that are in 52.3 g of lithium hypochlorite, we must first find the amount of moles. We do this by dividing by the molar mass of lithium hypochlorite.

52.3 g ÷ 58.4 g/mol = 0.896 mol

Next we must find the amount of formula units, we do this be multiplying by Avagadro's number.

0.896 mol × 6.02 × 10²³ = 5.39 × 10²³ f.u.

Now to get the amount of atoms we can multiply the amount of formula units by the amout of atoms in one formula unit.

5.39 × 10²³ f.u. × 3 atom/f.u. = 1.62 × 10²⁴ atoms

1.62 × 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

dsdrajlin

There are 1.62 × 10²⁴ atoms in 52.3 g of lithium hypochlorite.

First, we will convert 52.3 g to moles using the molar mass of LiClO (58.4 g/mol).

[tex]52.3 g \times \frac{1 mol}{58.4 g} = 0.896 mol[/tex]

Then, we will convert 0.896 moles to molecules using Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

[tex]0.896 mol \times \frac{6.02 \times 10^{23} molecule }{1 mol} = 5.39 \times 10^{23} molecule[/tex]

According to the chemical formula, there are 3 atoms in each molecule of  LiClO. The number of atoms in 5.39 × 10²³ molecules of LiClO is:

[tex]5.39 \times 10^{23} molecule \times \frac{3 atom}{1 molecule} = 1.62 \times 10^{24} atom[/tex]

There are 1.62 × 10²⁴ atoms in 52.3 g of lithium hypochlorite.

You can learn more about Avogadro's number here: https://brainly.com/question/13302703

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