Answer:
see explanation
Step-by-step explanation:
Using the rules of exponents
• [tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]
• [tex]a^{0}[/tex] = 1
• [tex]a^{m}[/tex] × [tex]a^{n}[/tex] ⇔ [tex]a^{(m+n)}[/tex]
Given
(a)
[tex]8^{-2}[/tex] = [tex]\frac{1}{8^{2} }[/tex]
(b)
[tex]\frac{1}{3^{-3} }[/tex] = 3³
(c)
[tex]6^{-12}[/tex] × [tex]6^{8}[/tex] × [tex]6^{0}[/tex]
= [tex]6^{(-12+8)}[/tex] × 1
= [tex]6^{-4}[/tex]
= [tex]\frac{1}{6^{4} }[/tex]
