Two dams, when opened, release water at different rates. The following functions represent the amounts of water the dams release over t minutes:
Dam A f(t) = 5t – 7t – 1
Dam B g(t) = 3t 2 + 4t + 9

Which function represents the difference in the amounts of water released, h(t) = f(t) – g(t)?


Options:
h(t) = 3t 2 – 5t + 11t + 10
h(t) = 2t 2 – 11t – 10
h(t) = 5t – 3t 2 – 3t + 8
h(t) = 5t – 3t 2 – 11t – 10

Respuesta :

Answer:

Step-by-step explanation:

h(t) = 2t 2 – 11t – 10 is the answer

The value of h(t) is h(t) = 2t^2 – 11t – 10.

To add or subtract functions, just add or subtract the values at each point where it makes sense.

How to find h(t) = f(t) – g(t)?

Two dams, when opened, release water at different rates. The following functions represent the amounts of water the dams release over t minutes:

Given : Dam A  f(t) = 5t^2 – 7t – 1

Dam B : g(t) = 3t ^2 + 4t + 9.

Then f(t) – g(t) = (5t^2-7t-1) -(3t^2+4t+9)

=> 2t^2 – 11t – 10.

Thus, h(t) = 2t^2 – 11t – 10.

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