Answer:
The valves perform above expectations.
Step-by-step explanation:
We are given the following information in the question:
Population mean, μ = 7.6 pounds per square inch
Sample size, n = 140
Sample mean, [tex]\bar{x}[/tex] = 7.8 pounds per square inch
Population standard deviation = 1.0 pounds per square inch
Level of significance = 0.05
We design the null and alternate hypothesis:
[tex]H_0[/tex] :  μ = 7.6 pounds per square inch
[tex]H_A[/tex]:  μ > 7.6 pounds per square inch
Formula:
[tex]z_{stat} = \displaystyle\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z_{stat} = \displaystyle\frac{7.8-7.6}{\frac{1}{\sqrt{140}}}[/tex]
[tex]z_{stat} = 2.366[/tex]
Now, we are performing a one tail test with level of significance of 0.05, we calculate the critical value of z with the help of standard normal distribution table.
Thus, [tex]z_{critical}[/tex] = 1.645
Result:
Since, [tex]z_{stat} > z_{critical}[/tex]
[tex]H_{0}[/tex] is rejected.
Thus, we accept the alternate hypothesis.
Hence, the valve perform above expectations.