Answer:
The change of the volume of the device during this cooling is [tex]14.3\times10^{-3}\ m^3[/tex]
Explanation:
Given that,
Mass of oxygen = 10 g
Pressure = 20 kPa
Initial temperature = 110°C
Final temperature = 0°C
We need to calculate the change of the volume of the device during this cooling
Using formula of change volume
[tex]\Delta V=V_{2}-V_{1}[/tex]
[tex]\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})[/tex]
Put the value into the formula
[tex]\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)[/tex]
[tex]\Delta V=14.297\ L[/tex]
[tex]\Delta V=14.3\times10^{-3}\ m^3[/tex]
Hence, The change of the volume of the device during this cooling is [tex]14.3\times10^{-3}\ m^3[/tex]
