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How much time does it take the satellite to complete one revolution? Scientists want to place a 3300 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:

Respuesta :

Answer:

[tex]T = 5.45 h[/tex]

Explanation:

As we know that time period of one revolution around Mars is given as

[tex]T = 2\pi\sqrt{\frac{r^3}{GM}}[/tex]

here we know that

[tex]r = 2.2 R[/tex]

here we know that radius of Mars is given as

[tex]R = 3.396 \times 10^6 m[/tex]

mass of Mars is given as

[tex]M = 6.42 \times 10^{23} kg[/tex]

now we have

[tex]T = 2\pi \sqrt{\frac{(2.2\times 3.396 \times 10^6)^3}{(6.67 \times 10^{-11})(6.42\times 10^{23})}}[/tex]

[tex]T = 19608 s[/tex]

[tex]T = 5.45 h[/tex]

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