If a sunspot has a temperature of 4,760 K and the solar surface has a temperature of 5,800 K, how many times brighter is the surface compared to the sunspot? (Hint: Use the Stefan-Boltzmann law.)

Respuesta :

Answer:

Brightness of sun surface = 2.2045 times of brightness of sunspot

Explanation:

We have given temperature of sunspot [tex]T_1=4760K[/tex]

Temperature of solar surface [tex]T_2=5800K[/tex]

Now according to Stefan's law

[tex]\frac{L}{A}=\sigma T^4[/tex], here L is radiated power, A is area, [tex]\sigma[/tex] is stefan constant

As the brightness depends on the radiated power

So [tex]\frac{brightness\ of\ sunspot}{brightness\ of\ sun\ surface}=\frac{T_1^4}{T_2^4}[/tex]

[tex]\frac{brightness\ of\ sunspot}{brightness\ of\ sun\ surface}=\frac{4760^4}{5800^4}=0.4536[/tex]

Brightness of sun surface = 2.2045 times of brightness of sunspot