Answer:
1) No, the car does not travel at constant speed.
2) V = 9 ft/s
3) No, the car does not travel at constant speed.
4) V = 5.9 ft/s
Explanation:
In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:
V(t) = 2*t + 2 Since the speed depends on time, the speed is not constant at any time.
For the average speed we evaluate the formula for t=2 and t=5:
d(2) = 8 ft and d(5) = 35 ft
[tex]V_{2-5}=\frac{d(5)-d(2)}{5-2}=9 ft/s[/tex]
Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:
d(1.8) = 6.84 ft and d(2.1) = 8.61 ft
[tex]V_{1.8-2.1}=\frac{d(2.1)-d(1.8)}{2.1-1.8}=5.9 ft/s[/tex]
Based on the formula that expresses the distance, the following is true:
Car average speed = Distance / Time
Distance = t² + 2t Time is a constant
Differentiating would give:
Average speed = 2t + 2
As the speed is dependent on the value of t, the speed cannot be constant. This also applies to the second question.
= Distance / Time
= t² + 2t / t
= ((5² + 2 x 5) - (2² + 2 x 5)) / (5 - 2)
= 7 ft/s
= t² + 2t / t
= ((2.1² + 2 x 2.1) - (1.8² + 2 x 1.8)) / (2.1 - 1.8)
= 5.9 ft/s
Find out more on average speed at https://brainly.com/question/6504879.
