contestada

An electrochemical cell has a constant potential of 2 V and provides a steady current of 1 A. How many electrons move from the anode to the cathode in 1000 seconds? (Use F = 1x105 C/mol e- )

Respuesta :

Answer:

[tex]n=6.25\times 10^{21}[/tex]

Explanation:

Potential across the electrochemical cell, V = 2 V

Current, I = 1 A

Time, t = 1000 s

Let n electrons move from the anode to the cathode. We know that electric current is calculated as :

[tex]q=I\times t[/tex]

Also, q = ne

[tex]ne=It[/tex]

[tex]n=\dfrac{It}{e}[/tex]

[tex]n=\dfrac{1\times 1000}{1.6\times 10^{-19}}[/tex]

[tex]n=6.25\times 10^{21}[/tex]

So, [tex]6.25\times 10^{21}[/tex] electrons move from the anode to the cathode in 1000 seconds.

Otras preguntas