3.50 g of an unknown base is dissolved in 289 mL of water and has a concentration of 0.219 M. What is the the identification of the unknown base.

Respuesta :

Answer:

The unknown base should be KOH whose molar mass is 56 g per mol (Answer)

Explanation:

Molarity = moles /(Volume in liters)  

So,  

Moles = Molarity [tex]\times[/tex] Volume

[tex]\\$=0.219 M \times 289 m L$\\\\$=0.219 \frac{m o l}{L} \times 0.289 L$\\\\$=0.063291 \mathrm{mol}$[/tex]

Molar mass = mass/moles

[tex]\\\\$=\frac{3.50 \mathrm{g}}{0.063291 \mathrm{mol}}=55.3 \mathrm{g}$ per mole[/tex]

The unknown base should be KOH whose molar mass is 56 g per mol (Answer)