Answer:
mass of methanol = 519.3 g
Explanation:
Given data:
molecules of CH3OH = 9.77 × 10∧ 24
mass in gram = ?
Solution:
First of all we will calculate the number of moles:
(9.77 × 10∧ 24) × 1 mol / 6.02 × 10∧23 = 16.229 moles
Now we will calculate the mass in gram:
Formula:
number of moles = mass/ molar mass
16.229 mole = mass / 32 g/mol
mass = 16.229 mol × 32 g/ mol
mass = 519.3 g
Simple method:
molar mass of CH3OH is 32 g so according to Avogadro number,
32 g of CH3OH = 6.02 × 10∧23 molecules
9.77*10^24 molecules will be equal to
(32 g of CH3OH / 6.02 × 10∧23 molecules) × 9.77*10^24 molecules
= 5.136 × 10∧-23 g/molecules × 9.77*10^24 molecules
= 519.3 g
