Answer : The amount of work this pump can do in kJ/kg is, [tex]4.2kJkg^{-1}[/tex]
Explanation :
Conversion used :
[tex]1kPacm^3=1000Pacm^3[/tex]
[tex]1000Pacm^3=1000Pa\times 10^{-6}m^3=10^{-3}Pam^3[/tex]
And,
[tex]1Pam^3=1J[/tex]
So,
[tex]10^{-3}Pam^3=10^{-3}J[/tex]
or,
[tex]10^{-3}Pam^3kg^{-1}=10^{-3}Jkg^{-1}[/tex]
so,
[tex]1kPacm^3kg^{-1}=10^{-3}\times 10^{-3}kJkg^{-1}[/tex]
As we are given that,
work of pump = [tex]4.2\times 10^6kPacm^3kg^{-1}[/tex]
So, the work of pump in kJ/kg is:
work of pump = [tex]4.2\times 10^6kPacm^3kg^{-1}\frac{10^{-3}\times 10^{-3}kJkg^{-1}}{1kPacm^3kg^{-1}}[/tex]
work of pump = [tex]4.2kJkg^{-1}[/tex]
Therefore, the amount of work this pump can do in kJ/kg is, [tex]4.2kJkg^{-1}[/tex]
