Explanation:
The given data is as follows.
Mass of apple sauce mixture = 454 kg
Heat added (Q) = 121300 kJ
Heat capacity ([tex]C_{p}[/tex]) of apple sauce at [tex]32.8^{o}C[/tex] = 4.0177 [tex]kJ/kg^{o}C[/tex]
So, Heat given by heat exchanger = heat taken by apple sauce
Q = [tex]mC_{p} \Delta T[/tex]
or, Q = [tex]mC_{p} (T_{f} - T_{i})[/tex]
Putting the given values into the above formula as follows.
Q = [tex]mC_{p} (T_{f} - T_{i})[/tex]
121300 kJ = [tex]454 kg \times 4.0177 kJ/kg^{o}C \times (T_{f} - 10)[/tex]
[tex]T_{f}[/tex] = [tex]76.5^{o}C[/tex]
Thus, we can conclude that outlet temperature of the apple sauce is [tex]76.5^{o}C[/tex].
