Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded to the tenths?

Question 5 options:

20 cm


7.2 cm


4.5 c

Respuesta :

Answer:

[tex]4.5 cm=L2[/tex]

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

[tex]H=\sqrt{L1^{2}+L2^{2}  }[/tex]

Where:

[tex]H=6 cm[/tex]

[tex]L1=4 cm[/tex]

[tex]L2=?[/tex]

We isolate our incognita an we get:

[tex]\sqrt{H^{2}-L1^{2}} =L2[/tex]

We supplant with the given data:

[tex]\sqrt{(6cm)^{2}-(4cm)^{2}} =L2[/tex]

[tex]\sqrt{36cm^{2}-16cm^{2}} =L2[/tex]

[tex]\sqrt{36cm^{2}-16cm^{2}} =L2[/tex]

[tex]\sqrt{20cm^{2}} =L2[/tex]

[tex]4.5 cm=L2[/tex]