Answer:
(a) 8.0 mg/l
(b) 7.8 mg/l
Explanation:
(a) We can calculate the chlorine concentration as
[tex]C_{Cl2}=\frac{28lbs}{6,000,000gal}*\frac{453,592.37}{1lb}*\frac{3.78541l}{1gal}\\\\C_{Cl2}=8,0 mg/l[/tex]
(b) In a steady system, the chlorine consumed is equal to the original chlorine concentration less the chlorine residue.
[tex]C_{consumed} = C_{0}-C_{residue}\\C_{consumed} = 8.0-0.2 = 7.8 mg/l\\[/tex]