Respuesta :
Explanation:
The given reaction equation is as follows.
[tex]2A + B \rightarrow C[/tex]
So, rate constants for different reactants and products written as follows.
[tex]\frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}[/tex]
As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.
A = -2
B = -1
C = 1
Therefore,
[tex]\frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}[/tex]
[tex]\frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}[/tex]
[tex]\frac{-k_{A}}{-2} = k_{B} = k_{C}[/tex]
Hence, [tex]k_{B} = k_{C}[/tex] = [tex]\frac{25}{2} (L/mol)^{2}[/tex]
= 12.5 [tex](L/mol)^{2}[/tex]
Thus, we can conclude that [tex]k_{B}[/tex] and [tex]k_{C}[/tex] are 12.5 [tex](L/mol)^{2}[/tex].
