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An ideal gas with MW = 30 is flowing at a steady rate through a circular pipe (cross-section area of 57.8 cm^2) at a temperature of 1.60 × 10^2 °C and pressure of 49.3 psig. The volumetric flow rate is 940 L/min, what is the molar flow rate (mol/s)?

Respuesta :

Answer:

n = 1.48 mol/s

Explanation:

ideal gas:

  • PV = RTn

⇒ n = PV/RT

∴ T = 1.60 E2 °C = 160°C = 433 K

∴ R = 0.082 atm.L/K.mol

∴ P = 49.3 psig * ( atm/ 14.6959psig ) = 3.35 atm

∴ V = 940 L/min

⇒ n =  (( 3.35 )*( 940 )) / (( 0.082 )*( 433 ))

⇒ n = 88.813 mol/min * ( min / 60s )

⇒ n = 1.48 mol/s

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