Answer: 26138g/mol
Explanation:
[tex]\pi =CRT[/tex]
[tex]\pi[/tex] = osmotic pressure = 12 mmHg =[tex]\frac{1}{760}\times 12=0.016[/tex] atm (760 mmHg= 1atm)
C= concentration in Molarity
R= solution constant = 0.0821 Latm/Kmol
T= temperature = [tex]10^0C=(10+273)K=283K[/tex]
For the given solution: 18 g of macromolecule is dissolved to make 1 L of solution.
[tex]Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution in ml}}[/tex]
[tex]C=\frac{18\times 1000}{M\times 1000ml}=\frac{18}{M}[/tex]
[tex]0.016=\frac{18}{M}\times 0.0821\times 283}[/tex]
[tex]M=26138g/mol[/tex]
The molecular weight of the macromolecule in grams per mole is 26138.
