Respuesta :
Explanation:
(a) The given data is as follows.
Water volume V = 1 [tex]ft^{3}[/tex]
At [tex]20^{o}C[/tex] weight of water w = 62.3 lbf
It i s known that 1 lbf = 32.174 [tex]lbm.ft.s^{-2}[/tex]
Then, weight w = [tex]62.3 \times 32.174[/tex] = 2004.4 [tex]lbm.ft.s^{-2}[/tex]
Weight = [tex]mass \times g[/tex]
where, g = gravitational acceleration in earth
and, Mass = [tex]density \times volume[/tex]
[tex]Density \times volume \times g[/tex]
= 2004.4 lbm. ft. s-2
[tex]Density \times 1 ft^{3} \times 32.174 ft/s^{2}[/tex] = [tex]2004.4 lbm. ft.s^{-2}[/tex]
Density = [tex]62.3 lbm/ft^{3}[/tex]
Hence, density of the water will be [tex]62.3 lbm/ft^{3}[/tex].
(b) When g = 6 [tex]ft/s^{2}[/tex] at moon then density and volume are not variable due to gravity.
weight (w) = [tex]Density \times volume \times g[/tex]
w = [tex](62.3 lbm/ft^{3}) \times 1 ft^{3} \times 6 ft/s^{2}[/tex]
= 373.8 [tex]lbm.ft.s^{-2}[/tex]
Hence, weigh on the moon is 373.8 [tex]lbm.ft.s^{-2}[/tex].
(c) Mass of any body is independent of the gravity, so density of the water is same as when it is at moon or earth.
Only weight of the body changes due to change in gravity.
It is known that 1 cubic miles = [tex]1.101 \times E12[/tex] us liquid gallon
and, 1 bbl = 42 US gallon
Therefore,
[tex]30 \times 10^{9} bbl = 42 \times 30 \times 10^{9} US gallon = 1260 \times E9 \text{us gallon}[/tex]
Hence,
total cubic miles = [tex]1260 \times \frac{E9}{1.101 \times E12}[/tex]
= 1.144 cubic miles
Thus, we can conclude that its density on the moon is 1.144 cubic miles.
By using what we know about density, we will get:
- a) 62.3 lb/ft^3
- b) 10.26 lbf
- c) 62.3 lb/ft^3.
How to get the density?
Remember that the density formula is:
Density = (mass)/(volume).
a) We know that 1 ft^3 of water weighs 62.3 lbf, then the mass of water is 62.3 lb.
Then the water density is:
D = (62.3 lb)/(1 ft^3) = 62.3 lb/ft^3
b) The gravitational acceleration on the moon is:
g = 5.3 ft/s^2
While in Earth, it is 32.17 ft/s^2
Then the weight in the moon will be:
W = (5.3 ft/s^2/32.17 ft/s^2)*62.3 lbf = 10.26 lbf
c) Notice that density is given by mass over volume, and the mass does not change in the moon (only the weight changes) so the density still is 62.3 lb/ft^3
If you want to learn more about density, you can read:
https://brainly.com/question/1354972
