Answer:
The Prandlt number for this fluid is 1630.
Explanation:
The Prandlt number is defined as:
[tex]Pr=\frac{C_p\mu}{k}[/tex]
To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.
[tex]\mu=1936\frac{lb}{ft*h}*\frac{1000g}{2.205lb}*\frac{3.281ft}{1m}*\frac{1h}{3600s} Â \\ \\\mu=800 \frac{g}{m*s}[/tex]
Now that we have coherent units, we can calculate Pr
[tex]Pr=\frac{C_p\mu}{k}=\frac{0.583*800}{0.286}= 1630[/tex]