Answer:
The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.
Explanation:
The heat flow through this area of the metal panel can be expressed as:
[tex]q/A=-k\frac{(T_2-T_1)}{Y}[/tex]
being A the surface area, k the thermal conductivity, T2 and T1 the temperatures in each side and Y the thickness of the metal panel.
We have to rearrange the equation to clear k:
[tex]k=\frac{-(q/A)*Y}{\Delta T} = \frac{-(3 W/100 cm2)*0.5cm}{5 ^\circ K}*(\frac{1m}{100cm} )^{3} \\\\k=\frac{0.015}{5*100^{3} }W/mK= 3*10^{-9}W/mK[/tex]
The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.