Respuesta :
Explanation:
The given data is as follows.
Boiler capacity = [tex]1 MT/hr \times 1000 kg/MT[/tex] = 1000 kg/hr
Steam pressure = 12 [tex]kg/cm^{2}[/tex]
For saturated steam, from steam table :
Steam temperature = [tex]187^{o}C[/tex]
Specific enthalpy of water = 794.65 kJ/kg
Specific enthalpy of steam = 2783.10 kJ/kg
Therefore, difference between enthalpy of steam and water will be calculated as follows.
= 2783.10 - 794.65
= 1988.45 kJ/kg
So, heat required will be calculated as follows.
Heat required = [tex]\text{boiler capacity} \times \frac{\text{enthalpy difference}}{\text{boiler efficiency}}[/tex]
= [tex]1000 kg/hr \times 1988.45 kJ/kg[/tex]
= 1988450 kJ/hr
Also, Fuel required = [tex]\frac{\text{heat required}}{\text{calorific value}}[/tex]
= [tex]\frac{1988450 kJ/hr}{150000 kJ/kg}[/tex]
= 13.25 kg/hr
Hence, Volumetric flow rate of hydrogen require = [tex]\frac{\text{fuel required}}{\text{density}}[/tex]
= [tex]\frac{13.25 kg/hr}{0.0899 kg/nm^{3}}[/tex]
= 147.45 [tex]nm^{3}/hr[/tex]
Thus, we can conclude that 147.45 [tex]nm^{3}/hr[/tex] hydrogen as a fuel will be burnt.
