The width of a rectangular park is 23.4 yards. What is the perimeter of the park if the length is 2.5 times larger than the width.

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mathstudent55 mathstudent55 · Answer 1 · 2019-09-24T23:18:59+02:00

Answer:

163.8 yd

Step-by-step explanation:

The perimeter of a rectangle is twice the length added to twice the width.

The width is 23.4 yd.

The length is 2.5 times the width, so to find the length, we multiply the width by 2.5.

length = 2.5 * width = 2.5 * 23.4 yd = 58.5 yd

The length is 58.5 yd.

perimeter = 2 * length + 2 * width

perimeter = 2 * 58.5 yd + 2 * 23.4 yd

perimeter = 117 yd + 46.8 yd

perimeter = 163.8 yd

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Wolfyy Wolfyy · Answer 2 · 2019-09-24T23:20:20+02:00

[tex]Hey![/tex]

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[tex]\large\boxed{Perimeter~of~the~retangular~park~is~163.8~yards!}[/tex]

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[tex]Steps To Solve:[/tex]

[tex]Find~the~length.[/tex]

[tex]23.4~*~2.5~=~58.5[/tex]

[tex]Find~the~perimeter.[/tex]

[tex]p~=~(length~*~2)~+~(width~*~2)[/tex]

[tex]p~=~(58.5~*~2)~+~(23.4~*~2)[/tex]

[tex]p~=~117~+~46.8[/tex]

[tex]p~=~163.8[/tex]

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[tex]Hope~This~Helped!~Good~Luck![/tex]