Answer:
The 95% confidence level is
[tex]4.17 \pm 0.2744[/tex]
Explanation:
If we can apply the central limit theorem, we can approximate this distribution to a normal distribution.
The confidence level (for n=1) is defined as
[tex]X\pm \frac{z*\sigma}{\sqrt{n}}=X\pm z*\sigma[/tex]
For a 95% confidence interval, according to the normal distribution, z=1.96.
Then we have:
[tex]X\pm z*\sigma=4.17 \pm 1.96*0.14=4.17 \pm 0.2744[/tex]
