Answer:
The x-coordinate is 0
Step-by-step explanation:
step 1
Find the slope m of the line
we have the points
(-10, 1) and (5,-5)
The formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
substitute the values
[tex]m=\frac{-5-1}{5+10}[/tex]
[tex]m=\frac{-6}{15}[/tex]
Simplify
[tex]m=-\frac{2}{5}[/tex]
step 2
Find the equation of the line in slope intercept form
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-intercept
we have
[tex]m=-\frac{2}{5}[/tex]
[tex]point\ (-10,1)[/tex]
substitute in the equation and solve for b
[tex]1=-\frac{2}{5}(-10)+b[/tex]
[tex]1=4+b[/tex]
[tex]b=1-4=-3[/tex]
The equation of the line is
[tex]y=-\frac{2}{5}x-3[/tex]
step 3
Find the x-coordinate of another point in the line if the y-coordinate is -3
For y=-3
substitute in the equation and solve for x
[tex]-3=-\frac{2}{5}x-3[/tex]
[tex]-3+3=-\frac{2}{5}x[/tex]
[tex]0=-\frac{2}{5}x[/tex]
[tex]x=0[/tex]
The point is (0,-3) -----> the y-intercept
therefore
The x-coordinate is 0
