Answer:
[tex]T = 1.38\times 10^{-2} K[/tex]
Explanation:
Given data:
wavelength = 21 cm
from wein's displacement relation we have
[tex]\lambda_{max} = \frac{b}{T}[/tex]
Where,
b is wein's constant and it is given as [tex]2.89 \times 10^{−3} m⋅K[/tex]
and T is temperature of radiation , [tex]\lambda_{max}[/tex] represent wavelength
Putting all value in the above equation to obtained desired temperature value
[tex]T = \frac{b}{\lambda_{max}}[/tex]
[tex]T = \frac{2.89\times 10^{-3}}{0.21}[/tex]
[tex]T = 1.38\times 10^{-2} K[/tex]
