Respuesta :

Answer:

Step-by-step explanation:

Steps:

1. Let x = #

2. "Five less than six times a number" can be written as: 6x - 5

3. "is at least" is the same as "greater than or equal to" and can be written as: >=

4. "nine subtracted from two times that number" can be written as: 2x - 9

5. the equation is: 6x - 5 >= 2x - 9

6. solve for x by grouping the x variable terms on one side and the constants on the other side:

6x - 5 >= 2x - 9

-2x +5 -2X +5

4x >= -4

7. divide each side by 4, and you get: x = -1

The solution according to the given statement is "x = -1".

According to the question,

The equation will be:

  • [tex]6x - 5 \geq 2x - 9[/tex]

By adding "5" both sides, we get

→ [tex]6x - 5+5 \geq 2x - 9+5[/tex]

→             [tex]6x \geq 2x-4[/tex]

By subtracting "2x" form both sides, we get

→     [tex]6x-2x \geq 2x-4-2x[/tex]

→             [tex]4x \geq -4[/tex]

→               [tex]x \geq -\frac{4}{4}[/tex]

→               [tex]x = -1[/tex]

Thus the above answer is appropriate.

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