The value of x in ln(3x + 2) = 4 is [tex]\bold{\frac{e^{4} - 2}{3}}[/tex]
Answer:
Option a
Solution:
From question, given that ln(3x + 2) = 4
ln(3x + 2) = 4 ----- eqn 1
By raising “e” to the power of both sides of equation, the above equation becomes
[tex]e^{\ln (3 x + 2)} = e^{4}[/tex]
“ln” and “e” cancel out each other in left hand side of above equation. Hence we get
[tex]3x + 2 = e^{4}[/tex]
Rearranging the terms, the above equation becomes,
[tex]3 x=e^{4}-1[/tex]
x = [tex]\frac{e^{4} - 2}{3}[/tex]
Thus the value of x in ln(3x + 2) = 4 is [tex]\bold{\frac{e^{4} - 2}{3}}[/tex]
