Answer:
The solution of [tex]\bold{\frac{M^{2}}{P^{2}}}[/tex] for M = 10, N = -5P and P = -2 is 25
Solution:
From question, given that the value of M is 10 and N is -5p and P is -2
We have to evaluate the value of [tex]\frac{M^{2}}{P^{2}}[/tex],
By substituting the values of M and N, we get
[tex]\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}[/tex]
Expanding [tex]\bold{10^{2}}[/tex]:
Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.
[tex]10^{2} = 10 \times 10 = 100[/tex]
Similarly expanding [tex]\bold{(-2)^{2}}[/tex]:
Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.
[tex](-2)^{2} = -2 \times -2 = 4[/tex]
So the equation [tex]\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}[/tex] becomes,
[tex]\frac{M^{2}}{P^{2}} = \frac{100}{4}[/tex]
By dividing 100 by 4 , we get the result as 25
Hence the solution of [tex]\bold{\frac{M^{2}}{P^{2}}}[/tex] when M = 10 and P = -2 is 25
