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Please solve this: a resident in a particular city pays a water bill of $3.51 per month plus $0.59 per 1000 gallons of water (used up to 4000 gallons). If the city has 561,000 costumers that use less than 4,000 gallons per month. Find it's monthly revenue function R(x). Where total number of gallons x measured in thousands. R(x)=

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sqdancefan

Answer:

  R(x) = 1,969,110 +0.59x . . . . in dollars

Step-by-step explanation:

The basic revenue to the city from the 561,000 customers will be ...

  561,000 × $3.51 = $1,969,110

The usage fee is still $0.59 per 1000 gallons, so the total for a total of x thousand gallons will be ...

  R(x) = $1,969,110 + $0.59x