what are the first four terms of the geometric sequence an=2 an-1 and a1=3

Answer:
3, 6, 12, 24
Step-by-step explanation:
This is a recursive formula which allows the next term in a sequence to be found from the previous term in the sequence
Given
[tex]a_{n}[/tex] = 2[tex]a_{n-1}[/tex] with a₁ = 3, then
a₂ = 2 × a₁ = 2 × 3 = 6
a₃ = 2 × a₂ = 2 × 6 = 12
a₄ = 2 × a₃ = 2 × 12 = 24
Thus the first 4 terms are 3, 6, 12, 24
Answer:
B.[tex]3,6,12,24[/tex]
Step-by-step explanation:
We are given that
[tex]a_n=2a_{n-1}[/tex]
[tex]a_1=3[/tex]
We have to find the first four terms of G.P
Substitute n=2
[tex]a_2=2a_1=2(3)=6[/tex]
Substitute n=3
[tex]a_3=2a_2=2(6)=12[/tex]
Substitute n=4
[tex]a_4=2a_3=2(12)=24[/tex]
Hence, the first four terms of G.P are given by
[tex]3,6,12,24[/tex]
Option B is true.