Respuesta :
Answer: 1290 Joules
Explanation:
Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure.
Amount of heat required to fuse 1 gram of gold = 64.5 J
Mass of gold given = 20 gram
Heat required to fuse 1 g of gold = 64.5 J
Thus Heat required to fuse 20 g of gold =[tex]\frac{64.5}{1}\times 20=1290J[/tex]
Thus 1290 Joules energy is required to melt 20.0 g of gold
