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A silo is shaped like a cylinder with a cone on top. The radii of the bases of the cylinder and cone are both equal to 8 feet. The height of the cylindrical part is 25 feet and the height of the cone is 6 feet. What is the volume of the entire silo?​

A silo is shaped like a cylinder with a cone on top The radii of the bases of the cylinder and cone are both equal to 8 feet The height of the cylindrical part class=

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SupaPreme
Answer: 6702.1

Explanation:
Volume of cylinder = πr^2h
= π(8^2)25
= 1600 π

Volume of cone = πr^2(h/3)
= π(8^2)(25/3)
= π (64)(25/3)
= (1600 π)/3

Add these two numbers
= 1600 π + (1600 π)/3
= (4800 π+ 1600 π)/3
= 6400 π/ 3
=6702.06≈6702.1

Answer:

Volume of the entire silo = 5428.67 ft³

Step-by-step explanation:

Here we need to add volume of cylinder to volume of cone.

[tex]\texttt{Volume of cylinder =}\pi r^2h[/tex],

Where r is the radius of cylinder and h is the height of cylinder.

[tex]\texttt{Volume of cone =}\frac{1}{3}\pi r^2h[/tex]

Where r is the radius of cone and h is the height of cone.

Radius of cylinder = 8 feet

Height of cylinder = 25 feet

Radius of cone = 8 feet

Height of cone = 6 feet

Substituting

             [tex]\texttt{Total volume = Volume of cylinder + Volume of cone}\\\\\texttt{Total volume =}\pi \times 8^2\times 25+\frac{1}{3}\times \pi \times 8^2\times 6=5428.67ft^3[/tex]

Volume of the entire silo = 5428.67 ft³

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