contestada

a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the magnitude of momentum of the skater.

Respuesta :

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) [tex]p[/tex] is given by the following equation:

[tex]p=m.V[/tex]

Where:

[tex]m=45 kg[/tex] is the mass of the skater

[tex]V[/tex] is the velocity

In this situation the skater has two values of momentum:

Initial momentum: [tex]p_{1}=m.V_{1}[/tex]

Final momentum: [tex]p_{2}=m.V_{2}[/tex]

Where:

[tex]V_{1}=3 m/s[/tex]

[tex]V_{1}=5 m/s[/tex]

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

[tex]p=p_{2}-p_{1}=m.V_{2}-m.V_{1}[/tex]

[tex]p=m(V_{2}-V_{1})[/tex]

[tex]p=45 kg(5 m/s - 3 m/s)[/tex]

Finally:

[tex]p=90 kgm/s[/tex]

Answer: 90m

Explanation:I hope this helps