Respuesta :
Answer:
StartFraction R Q Over P Q EndFraction
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle PQR the function sine of angle P is equal to divide the opposite side to angle P (segment RQ) by the hypotenuse (segment PQ)
so
[tex]sin(P)=\frac{RQ}{PQ}[/tex]
therefore
StartFraction R Q Over P Q EndFraction

Answer:
its d i took the test
Step-by-step explanation: