What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?

(–6, 0), (2,0)
(–2, –16), (0, –12)
(–6, 0), (–2, –16), (2, 0)
(0, –12), (–6, 0), (2, 0)

Respuesta :

the answer is A (-6,0) (2,0)

Answer:

Coordinates are (–6, 0), (2,0).

Step-by-step explanation:

Given the function [tex]f(x) = x2+4x-12[/tex]

we have to find the x-intercepts of the graph of the function f(x).

[tex]y = x2+4x-12[/tex]

As the value of y coordinate is 0 on x-axis which gives the x-intercepts of the function.

Put y=0 in above function we get the x-intercepts.

[tex]x^2+4x-12=0[/tex]

⇒ [tex]x^2+6x-2x-12=0[/tex]

⇒ [tex]x(x+6)-2(x+6)=0[/tex]

⇒ [tex](x-2)(x+6)=0[/tex]

⇒ x=2 and x=-6

Hence, x-intercepts are 2 and -6

⇒ Coordinates (–6, 0), (2,0).

Option 1 is correct.