What is the root of the polynomial equation x(x-2)(x+3)=18 ? Use a graphing calculator and a system of equations.
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tkmaplethorpepaykzs tkmaplethorpepaykzs · Answer 1 · 2018-08-10T21:12:45+02:00

It has four choses and you didn't show the right one, answer is 3.

3(3-2)(3+3)=18

3(1)(6)=18

3*6=18

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Аноним Аноним · Answer 2 · 2018-11-29T09:38:05+01:00

Answer:

3 is the root of the equation.

Step-by-step explanation:

We have to find the root of the polynomial equation x(x-2)(x+3)=18.

We can find the same by using a graphing utility and the system of equations.

We can make two equations which are given by

[tex]y=x(x-2)(x+3)....................(1)\\\\y=18[/tex]

Now, we plot the graph of these equations and the x-coordinate of the intersection point will be the root of the equation.

the graph has been shown in the attached file.

The intersection point is (3, 18) and the x-coordinate is 3.

Therefore, 3 is the root of the equation.