kmsperdindhirian
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A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds:

f(t) = −16t2 + 48t + 100

The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is _____feet per second.

Respuesta :

nobillionaireNobley
[tex]f(t) = -16t^{2} +48t + 100[/tex]
Average rate of change from t = 3 seconds to t = 5 seconds = [tex] \frac{f(5)-f(3)}{5-3} = \frac{(-16( 5^{2})+48(5)+100)-(-16( 3^{2})+48(3)+100 }{2}= [/tex][tex] \frac{(-16(25)+240+100)-(-16(9)+144+100)}{2} = \frac{(-400+240+100)-(-144+144+100)}{2}=[/tex] [tex] \frac{-60-100}{2} = \frac{-160}{2} = -80[/tex]

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