Carajayde9Love
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Choose the equation that could be used to find three consecutive integers whose sum is 36.

n + (n + 2) + (n + 4) = 36

n + (n + 1) + (n + 3) = 36

n + (n + 1) + (n + 2) = 36

n + (n − 1) + (n − 3) = 36

Respuesta :

n +(n+1) + ( n+2)=36
the third answer
calculista

Let

n--------> the first integer

n+1------> the second consecutive integer

n+2-----> the third consecutive integer

we know that

[tex]n+(n+1)+(n+2)=36\\3n+3=36\\3n=36-3\\3n=33\\n=33/3\\n=11[/tex]

the numbers are

[tex]11,12,13[/tex]

therefore

the answer is

The equation is [tex]n+(n+1)+(n+2)=36[/tex]

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