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The total energy of a 0.050 kg object travelling at 0.70 c is:

A) 2.10 × 107 J

B) 3.06 × 107 J

C) 2.46 × 1015 J

D) 6.30 × 1015 J

E) 8.82 × 1015 J

Respuesta :

What is the unit c denotes here
abidemiokin

Answer:

1.1025×10^15Joules

No correct option

Explanation:

The type of energy possessed by the object is kinetic energy. Kinetic energy is the energy due to virtue of an object motion.

KE = 1/2MV² where;

M is the mass of the car = 0.05kg

V is the velocity of the car

Since the car is traveling at 0.7c (c is the speed of light)

speed = 0.7c { 0.7(3×10^8)}

Speed = 2.1×10^8

Substituting this values in the formula given we have;

KE = 1/2×0.05×(2.1×10^8)²

KE = 1.1025×10^15Joules

No correct option.

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