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The end points of line segment AB are A(3,–12) and B(6,k).
What is the value of k if the slope of line segment AB is –2?

Pls. show me how to do it

Respuesta :

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(x,y) (3,-12) (6,k) y=mx+b sloope=m y=-2x+b sub known point (x,y) (3,-12) x=3 y=-12 -12=-2(3)+b -12=-6+b -6=b y=-2x-6 (6,k) k=-2(6)-6 k=-12-6 k=-18 k=-18

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