Answer:
Complete function will be [tex](2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)[/tex]
Step-by-step explanation:
We have given equation [tex](2x+3y)^2=(2x)^2+2\times (2x)\times (3y)+..........^2[/tex]
We have to find the function in place of blank space and complete the function
We know the algebraic equation [tex](a+b)^2=a^2+b^2+2ab[/tex]
So [tex](2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)[/tex]
So in place of blank pace there will be [tex](3y)^2[/tex]
And complete function will be [tex](2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)[/tex]
